50points! find the orbital speed of a satellite in a circular orbit 1700km above the surface of the earth. m_earth 5.97e24kg, r_avg_earth = 6.38e6m

Explanation:

The velocity of a satellite describing a circular orbit is constant and defined by the following expression:  

(1)  

Where:  

is the gravity constant

the mass of the massive body around which the satellite is orbiting, in this case, the Earth .

the radius of the orbit (measured from the center of the planet to the satellite).  

This means the radius of the orbit is equal to the sum of the average radius of the Earth and the altitude of the satellite above the Earth's surface .

Note this orbital speed, as well as orbital period, does not depend on the mass of the satellite. It depends on the mass of the massive body (the Earth).

Now, rewriting equation (1) with the known values:

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.

blue light is scattered in different directions by the tiny molecules of air. blue is scattered more than other colours because it has a shorter distance to travel which results in smaller waves. this is why we see a blue sky most of the time.