If the mass of the marble is 0.025kg, and you assume that on the first drop of your roller coaster (height=8cm) the marble is falling at exactly the rate of gravity (9.8m/s^2), what is the force of the marble? what is its potential energy in the beginning?

1. What is the force of the marble?

For an object near the surface of the earth, the gravitational force acting upon the object is given by:

F = mg

F is the gravitational force, m is the object's mass, and g is the acceleration of objects due to earth's gravity.

Given values:

m = 0.025kg, g = 9.8m/s²

Plug in the given values and solve for F:

F = 0.025×9.8

F = 0.25N

2. What is the marble's potential energy at the start of its fall?

The gravitational potential energy of an object near the earth's surface is given by:

PE = mgh

PE is the potential energy, m is the object's mass, g is the acceleration of objects due to earth's gravity, and h is the object's relative height.

new given values:

h = 0.08m

Since F = mg, you can simply multiply F×h to get PE. Use the result from question 1:

PE = F×h

PE = 0.25×0.08

PE = 0.02J

2b2t

explanation:

2b2t

f is prop to m1xm2 double m1 double force