In 1994, susan williams of california blew a bubble-gum bubble with a diameter of 58.4 cm. if this bubble were rigid and the centripetal acceleration of the equilateral points of the bubble were 8.5*10^-2 m/s^2, what would the tangential speed of those points be?

On the galapagos islands charles studied finches

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.