Arescue plane is flying horizontally at a height of 132 m above the ground. the pilot spots a survivor and releases an emergency kit with a parachute. the kit descends at a constant vertical acceleration of and the initial plane horizontal speed is . assuming air resistance and wind are negligible, how far away from the survivor will the emergency kit hit the ground?

446 m

301 m

2.64 km

426 m

= 426 m

Time taken to reach Earth = t  

s = ut + ½at²  

Vertically initial velocity = u = 0  

Therefore;

132 = 0t + ½6.89t²  

=132/3.445 = t²  

= 38.316 = t²  

t = 6.19 s  

Range = horizontal distance = speed x time

                                               = 68.9 x 6.19

                                                ≈ 426 m  

Hence the emergency kit impacts the ground 426 m from the survivor  

the diagram which shows forces as either balanced = same speed or unbalanced = accelerarting

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