To verify that this expression for (vf)α has the correct units of velocity, you need to perform some unit analysis. begin by finding the equivalent of a volt in terms of basic si units. what is a volt in terms of meters (m), seconds (s), kilograms (kg), and coulombs (c)?

1 V = 1 kg m2 s−² C

1 V = 1 kg m2 s−³ A−1

(one kilogram meter squared per second cubed per ampere)

The work required to move an electric charge of one coulomb through an electrical potential difference of one volt,

    Joules = Newton x metre

     Volts = Nm / coulombs

    Newton = kg x metre / second ²

    Volts = kg x metre / second ² coulombs

Volt in terms of meters (m), seconds (s), kilograms (kg), and coulombs (c)

Coulomb = Amp * second

Volts = kg x metre / second ³ Amp

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.