Ineed asap.

the average time that it takes for the car to travel the first 0.25m

the average time to travel just between 0.25m and 0.50m

given the time taken to travel the second 0.25m section, the velocity would /s

1. Average time for the first 0.25 m: 2.23 s

Explanation:

The average time that it takes for the car to travel the first 0.25 m is given by the average of the first three measures, so:

2. Average time to travel between 0.25 m and 0.50 m: 0.90 s

Explanation:

First of all, we need to calculate the time the car takes to travel between 0.25 m and 0.50 m for each trial:

t1 = 3.16 s - 2.24 s = 0.92 s

t2 = 3.08 s - 2.21 s = 0.87 s

t3 = 3.15 s - 2.23 s =  0.92 s

So, the average time is

3. Velocity in the second 0.25 m section: 0.28 m/s

Explanation:

The average velocity in the second 0.25 m section is equal to the ratio between the distance covered (0.25 m) and the average time taken (0.90 s):

no simpler subs form complex ones. synthesise = make

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .