Select all that apply. a 0.200-kilogram ball sits on a shelf 2.00 meters from the floor and then falls to a point 1.00 meter from the floor. ignoring any affects due to friction, at this position its mechanical energy is 3.92 jits potential energy is 3.92 jits kinetic energy is 3.92 jits potential energy is 1.96 jits kinetic energy is 1.96 jits mechanical energy is 1.96 j

Mechanical energy of the ball will remain conserved

so here we have

so mechanical energy will remain same at all positions

Now when ball comes to position of 1 m height then potential energy is given as

Now since total mechanical energy is conserved so we will say

so we have

its mechanical energy = 3.92 J

its potential energy = 1.96 J

its kinetic energy = 1.96 J

= initial pressure

= final pressure = 2

= initial volume

= final volume = /4

= initial temperature = 20 c = 20 + 273 = 293 k

= final temperature = ?

using the equation