Aball is thrown straight down with a velocity of 19.6m/s what will be its velocity 2.0s after being released

39.2 m/s

Explanation:

Initial velocity of the ball, u = 19.6 m/s

final velocity of ball, v

Time, t = 2.0 s

The ball would accelerate due to gravity,

a = g = 9.8 m/s²

Using first equation of motion:

v = u + a t

⇒ v = 19.6 m/s + 9.8 m/s² × 2.0 s = 39.2 m/s

Thus, the velocity of ball after 2.0 s of release would be 39.2 m/s