Will mark brainliest. look at the circuit below. what is the voltage between points c and d? a. 6 vb. 0 vc. 1.5 vd. 3 v

Since two identical bulbs are connected in this circuit in series combination

So here same current will flow into the circuit

So here we can say

also we know that

also it is given that bulbs are identical so we have

as we have

so now we can say

so here voltage across C and D is 1.5 volts

The hard way:

-- The total resistance in the series circuit is 120 ohms.

-- The current in the circuit is (voltage)/(resistance) = 3/60 = 0.025 A

-- The resistance between C and D is 60 ohms.

-- The voltage across a resistance is (current) x (resistance) = (0.025 x 60) = 1.5 volts. (C)

The easy way:

-- In a series circuit, the total voltage of the power source divides among the circuit's components in proportion to their resistances.

-- Since the bulbs have equal resistances, each one will have 1/2 of the battery voltage across it.

-- (1/2) of (3 volts) = 1.5 volts (C)

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