Point charges q1 and q2 are separated by a distance of 60 cm along a horizontal axis. the magnitude of q1 is 3 times the magnitude of q2 . at which point a on the axis is the electric field zero?

d = distance between the two point charges = 60 cm = 0.60 m

r = distance of the location of point "a" where the electric field is zero from charge between the two charges.

= magnitude of charge on one charge

= magnitude of charge on other charge

= 3

= Electric field by charge at point "a"

= Electric field by charge at point "a"

Electric field by charge at point "a" is given as

= k /r²

Electric field by charge at point "a" is given as

= k /(d-r)²

For the electric field to be zero at point "a"

=

k /(d-r)² = k /r²

/(d-r)² = 3 /r²

1/(0.60 - r)² = 3 /r²

r = 0.38 m

r = 38 cm