What will the angle of refraction be for a ray of light passing from air into a sodium chloride crystal if the angle of incidence is 60.0°? the index of refraction of sodium chloride is 1.53. a. 13° b. 22° c. 34° d. 42° e. 48°

Using Snell's Law:  

n1 * sin(theta1) = n2 * sin(theta2)  

where  

n1 is the refractive index of the incident light (n1 = 1 in this case)  

theta1 is the angle of incidence  

n2 is the refractive index of the material that the light is entering (n2 = 1.53 in this case)  

theta2 is the angle of refraction  

n1 * sin(theta1) = n2 * sin(theta2)  

becomes  

1 * sin(60) = 1.53 * sin(theta2)  

or  

1 * 0.866 = 1.53 * sin(theta2)  

0.866 = 1.53 * sin(theta2)  

sin(theta2) = 0.866 / 1.53 = 0.566  

theta2 = arcsin(0.566) = 34 degrees (the angle of refraction)

It should be 34 degrees because i took the test

Explanation:

Took the test

the pull of gravity on the rocket decreases

waves moving from a fast medium to a slow medium will experience a reflection as light travels more slowly than red light. total internal reflection occurs when the critical angle is.