Two charged particles are attracted to each other with a force of 7.6 newtons. what will happen if the distance between them shrinks to one third of what it started at?

The complete equation is as follows:

Force between two charge particles = k * Q1 * Q2 / r^2,

where k is constant, Q1 is charge on 1 particle, Q2 is charge on the other particle and r is the distance between the particles.

From the equation, if the distance between them shrinks to one third of what it started at, then the force will be 1/(1/3)^2 = 9 times larger.

It will become 7.6*9 = 68.4 Newtons.

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14