Apoint p is placed exactly between two charges, q1 and q2. if the electric field experienced by point p due to charge q1 is 1.5 × 105 newtons/coulomb and the field due to charge q2 is 7.2 × 105 newtons/coulomb, what is the net electric field at point p? a. 1.5 × 105 newtons/coulomb b. 3.0 × 105 newtons/coulomb c. 5.7 × 105 newtons/coulomb d. 8.7 × 105 newtons/coulomb e. 9.0 × 105 newtons/coulomb

 D

Given data:

The electric field due to charge q₁  is (E₁) = 1.5 × 10⁵ N/C

The electric field due to charge q₂ is (E₂) = 7.2 × 10⁵ N/C

Determine the net electric field at point P (Enet) = ?

electric field measured in Newtons/coulomb

We know that,

        The net electric field (Enet) is vector sum of E₁ and E₂ caused by the charge q₁ and q₂ respectively

             Enet = E₁ + E₂

                       = (1.5 × 10⁵)+ (7.2 × 10⁵)

                       = 8.7 × 10⁵ Newtons/coulomb

The net electric field at point P is  8.7 × 10⁵ N/C

i believe the answer is a

see earlier