Read through the scenarios below and calculate the predicted change in kinetic energy of the object compared to a 50 kg ball traveling at 10 m/s. a 50 kg ball traveling at 20 m/s would have kinetic energy. a 50 kg ball traveling at 5 m/s would have kinetic energy. a 50 kg person falling at 10 m/s would have kinetic energy.

The formula for kinetic energy is  KE = (1/2) (mass) (speed²)

== The 50 kg ball traveling at 10 m/s has some kinetic energy.  

== A 50 kg ball traveling at 20 m/s would be moving at double the speed.  So it would have (2)² = 4 times as much kinetic energy.

== A 50 kg ball traveling at 5 m/s would be moving at 1/2 the speed. So it would have (1/2)² = 1/4 as much kinetic energy.

== A 50 kg person falling at 10 m/s would have exactly the same amount of kinetic energy as the 50 kg ball traveling at 10 m/s.

The kinetic energy in each case will varies as 4 times, 1/4 times and same value as the initial obtained kinetic energy.

Given data:

The mass of ball is, m = 50 kg.

The speed of ball is, v = 10 m/s.

The another value of speed is, v' = 20 m/s.

The third value of speed is, u = 5 m/s.

The fourth value of speed is, u' = 10 m/s.

The standard expression for kinetic energy is given as,

KE = (1/2)mv²

here,

m is the mass and v is the speed of the object.

For 50 kg ball traveling at 10 m/s, the kinetic energy is,

KE = (1/2)(50)(10)²

KE = 2500 J

== A 50 kg ball traveling at 20 m/s would be moving at double the speed.  So it would have (2)² = 4 times as much kinetic energy.

== A 50 kg ball traveling at 5 m/s would be moving at 1/2 the speed. So it would have (1/2)² = 1/4 as much kinetic energy.

== A 50 kg person falling at 10 m/s would have exactly the same amount of kinetic energy as the 50 kg ball traveling at 10 m/s.

Thus, we can conclude that the kinetic energy in each case will varies as 4 times, 1/4 times and same value as the initial obtained kinetic energy.

Learn more about the kinetic energy here:

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volts times amps 6 x 0.5 3w

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.