The half-life of carbon-14 is 5730 years. explain how to figure out the age of a substance that has 25% carbon-14 remaining. a) multiply 25% times 5730 years since only 25% of the carbon remains. b) divide 5730 years by 2 since carbon has gone through two half-lives. c) multiply 5730 years by 2 since two half-lives have gone by for carbon. d) multiply 4 times 5730 years since carbon has gone through 4 half-lives.

C

Explanation:

25% is two half lives.

Each half life requires 5730 years.

So two half lives requires  

2

×

5730

Related questions

 C)Multiply 5730 years by 2 since two half-lives have gone by for carbon.

Explanation:

Multiply 5730 years by 2 since two half-lives have gone by for carbon. 5730 years will go by and 50% will remain. When 25% is remaining, another 5730 years will have passed. Therefore, multiply 5730 years by 2.

c. rb

explanation:

the atomic radius of a chemical element is a measure of the size of its atoms, usually the mean or typical distance from the center of the nucleus to the boundary of the surrounding shells of electrons.

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: