Pitbulllover101 rutherford's famous gold foil experiments shot heavy particles at a thin sheet of gold foil. what did he observe, and why did these observations eventually result in the addition of a nucleus to the atomic model? some of the heavy particles bounced off the foil, because there are positive particles spread throughout the atom. some of the heavy particles bounced off the foil, because there is a dense, positive area in the atom. the heavy particles all passed straight through the foil, because the atoms are mostly empty space. the heavy particles all bounced off the foil, because the subatomic particles have mass and volume.

Some of the heavy particles bounced off the foil, because there is a dense, positive area in the atom.

Explanation:

As per the observation of experiment he observed that very few heavy particles in this experiment bounced off in opposite direction.

Due to this reverse direction motion we can conclude that there must be a small dense region in which there is same charge concentrated which will repel the heavy particle

This region is concluded in very small space because major proportion move out the foil without any deviation only few of the particles will return back.

So here we can say that correct option must be

Some of the heavy particles bounced off the foil, because there is a dense, positive area in the atom.

i think the correct answer from the choices listed above is option c. when the kinetic energy of particles in a liquid state decreases

explanation:

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz