Aspring with k = 500 n/m stores 704 j. how far is it extended from the equilibrium position

Given that:

k = 500 n/m,

work (W) = 704 J

spring extension (x) = ?

         we know that,

                      Work = (1/2) k x²

                          704 = (1/2) × 500 × x²

                            x = 1.67 m

A spring stretched for 1.67 m distance.

12000j is work done

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length