A0.50 kg weight suspended from a spring is pulled to 0.50 m below its equilibrium point if the spring has a spring has a spring constant of 50 n/m at what rate will the mass accelerate when it is released 13 25 6.3 50

Given that:

mass (m) = 0.5 Kg,

spring pulled (x) =0.50 m,

spring constant (k)= 50 N/m,

                   accelearation = ?

        we know that from Hook's law

                         F = k.x

                            = 50 × 0.5

                            =25 N

Also we know that Force = m. a

                                    25  = 0.5 × a

                                      a = 50 m/s²

÷

i think it's 35 meters

the ima (higher than 1m) will be greater than the ima with the height of 1m.