A9.00 kg mass is moving to the right with a velocity of 14.0 m/s. a 12.0kg mass is moving to the left with a velocity of 5.00 m/s. assuming that these two balls have a head on collision and stick together, what will be the final velocity of the combination?

3.143 m/s

Explanation:

m1 = 9 kg

u1 = 14 m/s

m2 = 12 kg

u2 = - 5 m/s

Let the velocity after the collision is V

By using the principle of conservation of momentum

Momentum of two bodies before collision = momentum of two bodies after collision

m1 x u1 + m2 x u2 = (m1 + m2) x V

9 x 14 - 12 x 5 = (9 + 12) x V

126 - 60 = 21 x V

V = 3.143 m/s

Thus, the velocity of the sticked bodies after the collision is given by 3.143 m/s.

i think the answer would be reserve.

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