Two tugboats pull a barge across the harbor. one boat exerts a force of 7.5 x 10^4n north, while the second boat exerts a force of 9.5 x 10^4n at 15 degrees north of west. precisely, in what direction does the barge move?

The barge move due to the pulling force of two boats as 47.3 degrees in north-west direction.

Force is the effect of pull or push due to which the object having a mass changes its velocity.

The force is of two types-

Two tugboats pull a barge across the harbor.

In the given situation, one boat exerts a force of in the direction of north and the the second boat exerts a force of  N at 15 degrees north in the direction of west.

For this situation the total force acting on the north direction can be given as,

Now the total force acting on the west direction can be given as,

The tangent theta for this situation can be given as,

Thus, the barge move due to the pulling force of two boats as 47.3 degrees in north-west direction.

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The barge moves at an angle 47.3°North of West.

The tug boats exert forces in different directions on the barge and the barge moves in the direction of the resultant force.

Draw a diagram representing the forces, as shown in the figure attached. The tug boat 1 exerts a force F₁ along North while the tug boat 2 exerts a force F₂ at an angle of 15° North of west.

Resolve the forces along the North and the West.

The force acting along the North is given by,

The force along the West is given by,

The resultant force F makes an angle θ North of West.

Therefore, from the diagram,

Hence,

Thus, the barge moves in a direction 47.3° North of West.

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000