A0.50 kilogram ball is held at a height of 20 meters. what is the kinetic energy of the ball when it reaches halfway after being released? a. 49 joules b. 98 joules c. 1.0 × 10^2 joules d. 1.1 × 10^2 joules

A. 49 joules

Step By Step Solution:

Via kinematic equations we can must first determine the velocity of this object after 10 meters (since halfway of 20 meters is 10).

Where the initial velocity is zero since it's held at a height of 20 meters, hence it's not moving initially, g is the average gravity on Earth 9.8 m/s^2 and d is the distance this object will travel so 10 meters. By plugging these values in we obtain:

And the equation for kinetic energy is :

So the kinetic energy halfway after being released is 49 joules.

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.