An apple dropped from an apple tree. the height of the tree was 2.5 m. what was the final speed of the apple right before landing? the correct answer is 7 m/s. i have no clue pls

The correct answer to the question is : 7 m/s.

EXPLANATION:

As per the question, the apple is at a height h = 2.5 m.

The initial velocity of the apple u = 0

We are asked to calculate the final velocity [ v ] of the apple before touching the ground.

As the apple is falling under gravity, then the acceleration produced on the apple is nothing else than acceleration due to gravity.

Hence, acceleration a = g =

From equation of kinematics , we know that -

                              ⇒  

                               ⇒

                               ⇒

                              ⇒  

                               ⇒                     [ans]

Hence, the final velocity is 7 m/s.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer