The acceleration of a freely falling body is about 10m/sec/sec. if the ball is dropped from the top of a building what would its velocity be after 2 seconds?

The velocity will be 20 meters per second

The final velocity will be 20 m/s

According to first law of motion

Vf = Vi + at

Here we are given with

Vf = ?

Vi = 0  because it started from 0

a = 10 m/s²

t = 2 sec

So putting the values in the equation we get

Vf = 0 + 10 x 2

Vf = 20

So velocity after 2 seconds will be 20 m/s

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.

it would be c. predictability