What is the kinetic energy (in joules) of a .2 kg softball thrown at a speed of 40 m/sec? (answer should be in correct units)

m = mass of the softball thrown = 0.2 kg

v = speed of the softball thrown = 40 m/sec

K = kinetic energy of the softball thrown = ?

Kinetic energy of an object is given as

K = (0.5) m v²

where m = mass of object  , v = speed of object

hence for softball thrown , kinetic energy is given as

K = (0.5) m v²

inserting the values

K = (0.5) (0.2) (40)²

K = 160 J

hence kinetic energy of the softball comes out to be 160 J

i think it would be 5