On a frictionless horizontal air table, puck a (with mass 0.252 kg ) is moving toward puck b (with mass 0.374 kg ), which is initially at rest. after the collision, puck a has velocity 0.115 m/s to the left, and puck b has velocity 0.650 m/s to the right. calculate î”k, the change in the total kinetic energy of the system that occurs during the collision.

The change in the total kinetic energy of the system that occurs during the collision is 0.010Joules

According to the law of collision;

Substituting the given parameters into the equation to get the velocity of puck A, we have;

Change in kinetic energy = kinetic energy before the collision - kinetic energy after the collision

Change in kinetic energy =

Change in kinetic energy =

Change in kinetic energy = 0.010 Joules

Hence the change in the total kinetic energy of the system that occurs during the collision is 0.010Joules

Learn more here: link

As we know that kinetic energy is given as

Here we can find the initial speed of puck A by momentum conservation

now here we will have initial kinetic energy of the mass is given as

now loss of energy is given as

magnets not strong enough

explanation:

answergravity;