Astudent sits at rest on a piano stool that can rotate without friction. the moment of inertia of the student-stool system is 4.5 kg⋅m2 . a second student tosses a 2.0 kg mass with a speed of 2.5 m/s to the student on the stool, who catches it at a distance of 0.35 m from the axis of rotation. what is the resulting angular speed of the student and the stool?

Here We can use principle of angular momentum conservation

Here as we know boy + projected mass system has no external torque

Since there is no torque so we can say the angular momentum is conserved

now we know that

m = 2 kg

v = 2.5 m/s

L = 0.35 m

I = 4.5 kg-m^2

now plug in all values in above equation

so the final angular speed will be 0.37 rad/s

can somebody give me the answer so i can graduate