150kg object takes 1.5minutes to travel 2,500 meter straight path it begins the trip traveling 120m/s and decelerates to a velocity of 20m/s whats its acceleration

Acceleration= -1.11 m/sec²

Date Given to us is

Mass = 150 kg

Time = 1.5 minutes = 90 seconds

Distance = 2500 meters

Initial Velocity = 120 m/s

Final Velocity = 20 m/s

Acceleration = ?

Solution:

By using First Equation of motion

Vf = Vi + at

Putting the values

20 = 120 + a (90)

Subtracting 120 on both sides

20-120 = 120 + a(90) - 120

-100 = 90 a

Dividing both sides by 90

-100/90 = 90 a / 90

-1.11 = a

So the acceleration is -1.11 m/s²

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