1. what is the average velocity of a car if it travels from position 25 m to a position of -7 m in 34 seconds ? 2. a rock is thrown up into the air. it reaches the apex of its flight and falls back down to the earth. at the top of the rocks flight, what is rock acceleration?

1.

x₀ = initial position of the car = 25 m

x = final position of the car = - 7 m

t = time taken by the car = 34 seconds

displacement of the car is given as

d = change in position = x - x₀ = - 7 - 25 = - 32 m

average velocity of the car is given as

V = d/t

V = - 32/34

V = - 0.94 m/s

2.

after the rock is thrown up in air , the only force acting on the rock is force of gravity in down direction. due to this force , the rock experience acceleration in down direction which is known as the acceleration due to gravity. the magnitude of this acceleration is constant and is given as 9.8 m/s²

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get

he kicked it 10 feet straight up into the air? i think this works.