Physics, 01.07.2019 17:30, tay3783

What % of an object’s mass is below the water line if the object’s density is 0.63g/ml?

Answers: 1

Show answers

Answers

According to the Archimedes’ Principle, a body totally or partially immersed in a fluid at rest, experiences a vertical upward thrust equal to the mass weight of the body volume that is displaced.

In this case we have an object partially immersed in water.

If we observe in the image attached, this object does not completely fall to the bottom because the net force acting on it is zero, this means it is in equilibrium.

This is due to Newton’s first law of motion: if a body is in equilibrium the sum of all the forces acting on it is equal to zero

$F_{total}=0$ (1)

Here, the object experiences two kind of forces:

A force downwards because of its weight:

(2)

Where is the mass of the object and the acceleration of gravity, which in this case (on earth) is $9.8\frac{m}{s^{2}}$

And a force applied upwards because of the buoyancy:

$F_{buoyancy}=d_{w}gV_{i}$ (3)

Where;

$d_{w}$ is the density of Water which is $1\frac{g}{ml}$

And $V_{i}$ is the volume of the immersed part of the object

Well, if the total net force exerted to the object is zero:

$F_{total}= F_{buoyancy}-W=0$ Note has a negative sign because this force is applied downwards

This means the buoyancy is equal to the weight:

$F_{buoyancy}=W$ (4)

$d_{w}gV_{i}=mg$ (5)

Dividing by in both sides:

$d_{w}V_{i}=m$ (6)

Now, the density of an object or fluid is the relation between the mass and the volume, in the case of the object of this problem is:

$d=\frac{m}{V}$ (7)

Where is the Volume of the object.

From (7) we can find the mass of the object:

(8)

and substitute this value in (6), in order to get a relation between the density of the object and the density of the water, as follows:

$d_{w}V_{i}= dV$

$\frac{V_{i}}{V} =\frac{d}{ d_{w}}$ (9)

$\frac{V_{i}}{V}=\frac{d}{d_{w}}=\frac{0.63g/ml}{1g/ml}$

Then;

$\frac{0.63g/ml}{1g/ml}=0.63$

This result is the same as $\frac{63}{100}$ which represents the $63\%$

Therefore the answer is:

$63\%$ of the mass of the object is below the water line or immersed in water

What % of an object’s mass is below the water line if the object’s density is 0.63g/ml?

What % of an object’s mass is below the water line if the object’s density is 0.63g/ml?

answered: Guest

answer: good job it's all correct !

explanation:

Iwill mark as the brainliest answer check if the answers are correct

answered: Guest

Amethod of procedure that has characterized natural science since the 17th century, consisting in systematic observation, measurement, and experiment, and the formulation, testing, and modification of hypotheses.

Other questions on the subject: Physics

Physics, 22.06.2019 13:40, crayons18

An ideal otto cycle has a compression ratio of 10.5, takes in air at 90 kpa and 40°c, and is repeated 2500 times per minute. using constant specific heats at room temperature, determine the thermal efficiency of this cycle and the rate of heat input if the cycle is to produce 90 kw of power.

Answers: 2

continue

Physics, 22.06.2019 14:30, chelseayazzie16

What distance does a car travel as its speed changes from 0 to 20 m/s in 17 s at constant acceleration?

Answers: 1

continue

Physics, 22.06.2019 16:30, makenahbriana

In a heat engine if 1000 j of heat enters the system and the piston does 500j of work, what is the final internal energy of the system if the inital energy was 2000 j1.write the equation2.list out your known variables 3. plug the numbers into the equations4.solve 5.write your solution statement that includes initial energy and final energy added.

Answers: 3

continue

Physics, 22.06.2019 17:00, Jasten

Since the energy was not raising the temperature of the water during these segments, what was the energy used to do instead? your answer must include an explanation of what is happening to the molecules.