A0.075 kg ball in a kinetic sculpture moves at a constant speed along a motorized vertical conveyor belt. the ball rises 1.32 m above the ground. a constant frictional force of 0.350 n acts in the direction opposite the conveyor belt's motion. what is the net work done on the ball?

0.51 J

Explanation:

The work done on the ball is equal to the sum of two terms:

- the work done in lifting the ball by 1.32 m

- the work done by the frictional force of 0.350 N that acts opposite to the motion; this work is negative, since the force acts in the opposite direction to the motion of the ball.

In formulas, the net work done is:

where

m = 0.075 kg is the ball's mass

g = 9.8 m/s^2 is the gravitational acceleration

h = 1.32 m is the height throug which the ball has been moved

Ff = 0.350 N is the frictional force

Substituting, we find

thermal energy is the answer

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle