Aworker sits at one end of a rod that is 2.80 m long. a weight of 107 n is placed at the other end of the rod. the rod is balanced when the pivot is 0.670 m from the worker. calculate the weight of the worker.

Let the weight of the worker represented by X newton.

There is a normal force  exerted at a distance of 0.67 m

A weight of 120 Newton is acting at distance of 2.8 m

Taking the moments of the across the pivot, we get:

107 N x (2.8 m-0.67 m) = X newton x o.67 Newton

X = 107 N x 2.13 m/0.67 m

X = 340.164 N

im not to sure what it is