A50- kg block of concrete is pulled upward (not sideways) with a force of 600 n =what is the acceleration

The weight of the block is (mass x gravity) = (50kg x 9.8 m/s²) = 490 N

The NET vertical force on the block is (490N down) + (600N up) = 110N up.

Acceleration = (net force) / (mass)

Acceleration = (110N up) / (50 kg)

Acceleration = 2.2 m/s² up

where are the vectors ?

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards