Ablock of mass 9.5kg rests on a slope an angle of 23.0∘ relative to the horizontal. what is the size of the contact force normal to the slope, in newtons? use a gravitational acceleration value of g = 9.8m/s^2.

The Normal Force = M x G x Cos(theta)

= 9.5 Kg x 9.8 m/s^2 x cos 23

= 9.5 Kg x 9.8 m/s^2 x 0.9205

Converting Kg to Newton,

1 Kg  = 9.81 N

= 9.5 Kg x 9.81 N x 9.8 m/s^2 x 0.9205

= 840.702 N

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.