Plz a 24.0 kg brick is pushed across the floor with a force of 590 n. there is sliding friction. the acceleration of the brick is 7.04 m/s/s. calculate the sliding friction force.

Okay first raise your equation of Newton's second law:

∑Fx = ma;

Then visualize in a free body diagram what forces are acting in the body.

In this case, the force of 590N and the sliding friction force.

F - = ma

And just clear the friction force from the equation.

= F - ma

Finally you substitute your values

590N - (24Kg)(7.04m/s^2) =

= 421.04N

mistakes are ok