Ayoung woman decides to jump out of a parachute. she falls for 3.14 seconds before her chute opens. calculate thr velocity when the canopy begins to open. neglect motion and air resistance.

The question is somewhat ironic, dontcha think ?.  We're talking about a young woman using a parachute in a situation where there is no air resistance.  Her immediate future safety is not encouraging.

Let's assume this scenario is taking place near the surface of planet Earth. Then, the acceleration of gravity is 9.8 m/s².  That means that at any time, a falling object is falling 9.8 m/s faster than it was falling one second earlier.

The young woman's falling speed is zero when she jumps out of the parachute (?).  After 3.14 seconds, it is (3.14 x 9.8 m/s) = 30.77 m/s faster than zero.

6/12=1/2

step-by-step explanation:

answer: b.

explanation: