Projectile motion problems a cat chases a mouse across a 2.5 m high table. the mouse steps out of the way, and the cat slides off the table and strikes the floor 2.2 m from the edge of the table. what was the cat's speed when it slid off the table?

This can be solved by separating the vertical and horizontal motion.

The cat slides off the table and drops with a vertical acceleration of gravity, g, and initial vertical velocity of zero.

Using the kinematic equation: s = ut + 1/2 a t^2,

and substitute s=2.5, u=0, a=g

2.5=1/2gt^2

t = sqrt(5/g)

Assume the cat slides off with a horizontal speed of V, its horizontal acceleration is zero.

Using the same kinematic equation: s = ut + 1/2 a t^2,

and substitute s=2.2, a=0, t=sqrt(5/g)

2.2 = u(sqrt(5/g)) + 1/2 (0) (%/g)

u = 2.2/(sqrt(5/g))

assuming g=9.8, u = 2.2/(sqrt(5/9.8))

u = 3.08 m/s

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explanation:

heat the gas and measure the pressure