When a mass of 5 kg hangs from a vertical wire of length 2 m, waves travel on this wire with a speed of 10 m/s. what will the speed of these waves be, if the mass is doubled without stretching the wire? 14 m/s 20 m/s 5.0 m/s 12 m/s

The speed of these waves will be 14 m/s

Let's recall the speed of wave formula as follows:

where:

c = speed of wave ( m/s )

λ = wavelength ( m )

f = frequency of wave ( Hz )

where:

v = speed of wave on string ( m/s )

T = tension in the string ( N )

μ = linear density ( kg/m )

Let us now tackle the problem!

Given:

initial mass = m₁ = 5 kg

length of vertical wire = L = 2 m

initial speed of wave = v₁ = 10 m/s

final mass = m₂ = 2m₁ = 2(5) = 10 kg

Asked:

final speed of wave = v₂ = ?

Solution:

Grade: High School

Subject: Physics

Chapter: Wave

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~