A0.25 kg baseball is in contact with a bat for 0.0075 s and exerts a force of 18,500 n. what impulse is delivered to the ball? 33 kg • 140 kg • 4600 kg • 74,000 kg •

Mass of base ball = 0.25kg

Time = t = 0.0075/s

Force = F = 18,500N

Impulse = J = ?

Formula = Impulse = Force x time

= 18,500x0.0075

= 138.75 N-S

Rounded: 140 kg

Impulse, J = 140 kg m/s

Explanation:

It is given that,

Mass of the baseball, m = 0.25 kg

Force exerted on the baseball, F = 18,500 N

Time of contact of baseball and bat is, t = 0.0075 s

We have to find the impulse delivered to the bat. Impulse is defined as the product of force and time. It is also equivalent to change in momentum.

So, J = F × t

J = 138.75 N-s

or

J = 140 kg m/s

Hence, this is the required solution.

a) the event horizon, singularity, and the chute located between the two.