Asample of a gas in a rigid container has an initial pressure of 5 atm at a temperature of 254.5 k. the temperature is decreased to 101.8 k. what is the new pressure? pls ! i give 8 points!

here since container is rigid so we can say here volume must be constant

so here we can say by ideal gas equation

PV = nRT

here we know that

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

so here if volume is given constant

so we can say

now we know that

now from above equation we will have

by solving above equation we will have

so final pressure will be 2 atm

multiple

the answer would be c. motion and direction

i hope this : )