An airplane accelerates down a runway at 3.20 m/s for 32.8 s until it finally lifts off the ground. determined the distance traveled before take off

Initial velocity is - 0 m /s.

Acceleration is - 3.20 m / s^2

Time - 32.8 s

According to the laws of motion.

S = ut + 1/2 at ^2

S = 1/2 at²

S = 1/2(3.20)(32.8)²

S = 1721.344 m

So the distance traveled before takeoff is 1731.3m

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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amplitude

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