Askier approaches the base of an icy hill with a speed of 12.5 m/s. the hill slopes upward at 24° above the horizontal. ignoring all friction forces, what is the acceleration of this skier when she is going up the hill? a)9.0 m/s2, directed down the slope b)4.0m/s2, directed down the slope c)4.0m/s2, directed up the slope d)9.0 m/s2, directed up the slope

when object is placed on inclined plane then we will have net force along the inclined plane which is due to the component of weight along the incline

so we can say that

now in order to find the acceleration we can use Newton's II law

and the direction is along the inclined plane downwards as weight always pull downwards

So correct answer will be

B)4.0m/s2, directed down the slope

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.

a. spokes of a wheel.

as indicated in the question radial contains rad, also found in radius, so the fracture's would span the radius.