Moving from 0m/s to 25m/s in 8.0s equals an average acceleration

Moving from 0m/s to 25m/s in 8.0s equals an average acceleration of 3.125 m/s^2. You get this through the following steps:

25-0/8-0 = 3.125 m/s^2

since the average acceleration (a) = change in vvelocity over change in time

3.125 m/s^2

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Average acceleration = 3.124 m/s²

Given data:

Initial velocity = 0 m/s

Final velocity = 25 m/s

Time = 8.00 s

Average acceleration = ?

Solution:

Average acceleration = (Final velocity - Initial velocity)/time

By putting values in above formula:

Average acceleration = (25 - 0)/8

                                  = 25/8

                                  = 3.125 m/s²

Hence an object moving from 0m/s to 25m/s of velocity in 8.0s has an average acceleration of 3.125 meter per second square. Acceleration is the rate of change of velocity. And average acceleration is equal to change in final velocity and initial velocity divided by time.

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it