Arock is thrown upward with an initial velocity of 9.6m/s to what hight does it rise and how long does it take to reach that high

Given:

u(initial velocity):9.6 m/s

at the maximum height final velocity =0

The acceleration acting on the body is gravity as it is free falling object

=-9.8m/s^2

Now we know that

v^2-u^2 = 2as

Where v is the final velocity measured in m/s

u is the initial velocity which is measured in m/s

a is the acceleration measured in m/s^2

s is the distance traveled by the rock in this case it is considered as the height

Substituting these values we get

0-9.6= 2 x -9.8 x s

s= 0.49 m

Consider t as the time taken for the rock to travel

v=u+at

0=9.6 -9.8t

t=0.98sec

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the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia