Aforce is applied to a box of 10.0 kg for 4.0 s. the box goes from rest to 25 m/s in that time. what is the magnitude of that force?

Given:

m(mass of the box)=10 Kg

t(time of impact)=4 sec

u(initial velocity)=0.(as the body is initially at rest).

v(final velocity)=25m/s

Now we know that

v=u+at

Where v is the final velocity

u is the initial velocity

a is the acceleration acting on the body

t is the time of impact

Substituting these values we get

25=0+a x 4

4a=25

a=6.25m/s^2

Now we also know that

F=mxa

F=10 x6.25

F=62.5N

glen is correct.

step-by-step explanation:

glen is correct because when you multiply 4 * 2 = 8.

and 4 * 3 = 12.