To win the game, a place kicker must kick a football from a point 28 m (30.6208 yd) from the goal, and the ball must clear the crossbar, which is 3.05 m high. when kicked, the ball leaves the ground with a speed of 18 m/s at an angle of 48◦ from the horizontal. the acceleration of gravity is 9.8 m/s 2 . by how much vertical distance does the ball clear the crossbar? answer in units of m.

v = 18cos48 m/s  

So time = distance/speed  

= 28/18cos48  

= 2.3247413  

Resolving vertically, now use s = ut + (0.5)a(t^2)  

Where s is the unknown distance (the height above the GROUND)  

u is initial (vertical) speed = 18sin48  

a = -9.8 m/s (negative since we take upwards as positive)  

t = 2.3247... (what we found previously)  

Putting the numbers into the formula gives 4.616126809  

Take away the height of the goalpost (3.05) = 1.566126809  

= 1.57m above the crossbar.

hope this helps :)

the independent variable, the one that is intentionally manipulated, is whether or not the car hits the barrier.

the dependent variable, the one that you measure the response in, is the distance that the washers travel.