For no apparent reason, a poodle is running at a constant speed of 5.00 m/s in a circle with radius 2.9 m . let v⃗ 1 be the velocity vector at time t1, and let v⃗ 2 be the velocity vector at time t2. consider δv⃗ =v⃗ 2−v⃗ 1 and δt=t2−t1. recall that a⃗ av=δv⃗ /δt. a) for δt = 0.4 s calculate the magnitude (to four significant figures) of the average acceleration a⃗ av. b) for δt = 0.4 s calculate the direction (relative to v⃗ 1) of the average acceleration a⃗ av. c) for δt = 0.2 s calculate the magnitude (to four significant figures) of the average acceleration a⃗ av. d) for δt = 0.2 s calculate the direction (relative to v⃗ 1) of the average acceleration a⃗ av. e) for δt = 7x10^-2 s calculate the magnitude (to four significant figures) of the average acceleration a⃗ av. f) for δt = 7x10^-2 s calculate the direction (relative to v⃗ 1) of the average acceleration a⃗ av.
Answers: 1
(where 1 revolution corresponds exactly to 360 degrees). We use this to determine how much of the circular path the poodle traverses in each given time interval with duration 
. Denote by 
the angle between the velocity vectors (same as the angle subtended by the arc the poodle traverses), then
for each time interval by using the law of cosines:
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For no apparent reason, a poodle is running at a constant speed of 5.00 m/s in a circle with radius...
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