Asailboat starts from rest and accelerates at a rate of 0.13 m/s2 over a distance of 458 m. (a) find the magnitude of the boat's final velocity. m/s (b) find the time it takes the boat to travel this distance. s

Given:

u(initial velocity): 0

a(acceleration): 0.13 m/s∧2

distance = 458 m

Now  s= ut +1/2 (at∧2)

Substituting from the given values we get

458= 0+ 1/2(0.13 x t∧2)

t = 83.94 secs

Now v (velocity)= u+ at

Substituting for t as 83.94 secs and for a and u from the given values we get:

v= 0+0.13 x t

v= 0.13 × 83.94

v=10.91 m/s

Therefore the final velocity of the boat is 10.91 m/s and the time taken for the boat to travel 458 m is 83.94 secs

d is the answer i came up with

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz