At a distance of 0.75 meters from its center, a van der graff generator interacts as if it were a point charge, with that charge concentrated at its center. a test charge at that distance experiences an electric field of 4.5 × 105 newtons/coulomb. what is the magnitude of charge on this van der graff generator?

Since the Van de Graaff generator is given to behave like a point charge, we can use the equation for Electric Field, given as

where, =

r is the distance between the generator and the test charge = 0.75 m

E is the magnitude of the Electric Field Strength =

Rearranging the equation, making Q the subject of the formula, we have

Plugging in the numerical values and simplifying them gets us

Thus, the charge on the Van de Graaff generator is 28.16 μC.

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