Cassy shoots a large marble (marble a, mass: 0.06kg) at a smaller marble (marble b, mass: 0.03kg) that is sitting still. marble a was initially moving at a velocity of 0.7m/s, but after the collision it has a velocity of -.02m/s. what is the resulting velocity of marble b after the collision? be sure to show your work.

The question can be solved using conservation of linear momentum.

= 0.06kg and = 0.03kg

Let the initial velocity of Marble A be , = 0.7m/s

Let the initial velocity of Marble B be, = 0m/s

Let the velocity of Marble A after collisiong , = -0,02m/s

Let the velocity of Marble B after collision be

From the conservation of linear momentum equation. We get,

Substituting the values we get,

(0.06)(0.7) + 0 = (0.06)(-0.02) + (0.03)

we get, = 1.44m/s