Two circular disks spaced 0.50 mm apart form a parallel-plate capacitor. transferring 1.50 ×109 electrons from one disk to the other causes the electric field strength to be 2.00 ×105n/c. what are the diameters of the disks?

The diameter of the disk at the given electrons is 13.1 mm.

The total charge of the capacitor is calculated as follows;

The potential difference between the disk is calculated as follows;

The capacitance of the capacitor is calculated as follows;

The area of the disk is calculated as follows;

The diameter of the disk is calculated as follows;

Learn more here:link

The diameter of the disks is 1.32 cm.

If n electrons each of charge e are transferred from one disc to another, calculate the total charge Q transferred from one disc to the other using the expression,

Substitute 1.50×10⁹ for n and 1.6×10⁻¹⁹C for e.

The potential difference V between the disks separated by a distance d is given by,

here, E is the electric field.

Substitute 2.00×10⁵N/C for E and 0.50×10⁻³m for d.

The capacitance C of the capacitor is given by,

The capacitance of a parallel plate capacitor is given by,

Here, ε₀ is the permittivity of free space  and A is the area of the disks.

Rewrite the expression for A.

the area A of the disks is given by,

Here, D is the diameter of the disk.

The diameter of each disc is found to be 1.32 cm.

colorectal cancer may also develop from areas of abnormal cells in the lining of the colon or rectum. this area of abnormal cells is called dysplasia and is more commonly seen in people with certain inflammatory diseases of the bowel such as crohn's disease or ulcerative colitis.

see earlier